Problem 1 · Differential equations
The Laplace transform of f(t) = 3e^(−2t) sin 4t is:
- A.12/[(s + 2)² + 16]
- B.12/[(s² + 16)(s + 2)]
- C.12/[(s − 2)² + 16]
- D.3(s + 2)/[(s + 2)² + 16]
Show the answer and solution
Answer: A: 12/[(s + 2)² + 16]
L{sin bt} = b/(s² + b²), and multiplying by e^(−at) shifts s to s + a. With b = 4 and a = 2: L{3e^(−2t) sin 4t} = 3(4)/[(s + 2)² + 16] = 12/[(s + 2)² + 16]. The transform of a product is not the product of the transforms, so the last option is wrong.
Differential equations · Reference Handbook: Mathematics
