Problem 1 · Analytic geometry
The boundary of an elliptical culvert opening is 9x² + 25y² = 225, with x and y in feet measured from the center. The distance between the two foci of the ellipse is most nearly:
- A.4 ft
- B.6 ft
- C.8 ft
- D.10 ft
Show the answer and solution
Answer: C: 8 ft
Dividing by 225 gives x²/25 + y²/9 = 1, so a = 5 ft and b = 3 ft. Then c = √(a² − b²) = √16 = 4 ft, and the foci are 2c = 8 ft apart. The value 4 ft is only the center-to-focus distance.
Analytic geometry · Reference Handbook: Mathematics
