Problem 1 · Newton's second law for rigid bodies
A 10 kg block hangs from a light rope wound around a drum of 0.25 m radius. The drum turns in frictionless bearings and has a mass moment of inertia of 2.0 kg·m². Take g = 9.81 m/s². When released, the block's acceleration is most nearly:
- A.2.34 m/s²
- B.3.07 m/s²
- C.5.45 m/s²
- D.9.81 m/s²
Show the answer and solution
Answer: A: 2.34 m/s²
Block: mg − T = ma. Drum: Tr = Iα = I(a/r), so T = Ia/r². Combining: a = mg/(m + I/r²) = 98.1/(10 + 32) = 2.34 m/s².
Newton's second law for rigid bodies · Reference Handbook: Dynamics
