Problem 1 · Stress and strain caused by axial loads
A solid steel hanger rod 20 mm in diameter and 2.5 m long carries an axial tensile load of 50 kN. Use E = 200 GPa. The elongation of the rod is most nearly:
- A.0.497 mm
- B.1.56 mm
- C.1.99 mm
- D.7.96 mm
Show the answer and solution
Answer: C: 1.99 mm
A = π(0.020)²/4 = 314.2 mm². δ = PL/(AE) = (50,000 N)(2.5 m)/[(3.1416e-04 m²)(200 × 10⁹ Pa)] = 1.989e-03 m = 1.99 mm. Using πd² instead of πd²/4 makes the area four times too large and gives 0.497 mm.
Stress and strain caused by axial loads · Reference Handbook: Mechanics of Materials
