Problem 1 · Flow measurement
A pitot-static tube in a water pipe is connected to a mercury differential manometer (SG = 13.6) that reads 60 mm. Take g = 9.81 m/s². The water velocity at the tube is most nearly:
- A.1.08 m/s
- B.2.72 m/s
- C.3.85 m/s
- D.4.00 m/s
Show the answer and solution
Answer: C: 3.85 m/s
The stagnation-minus-static head in meters of water is h = 0.060(13.6 − 1) = 0.756 m. V = √(2gh) = √[2(9.81)(0.756)] = 3.85 m/s. The water filling the manometer legs above the mercury is why (SG − 1) is used, not SG alone.
Flow measurement · Reference Handbook: Fluid Mechanics
