Problem 1 · Area properties
A solid circular shaft has a diameter of 80 mm. The radius of gyration of its cross-sectional area about a diameter is most nearly:
- A.20.0 mm
- B.23.1 mm
- C.28.3 mm
- D.40.0 mm
Show the answer and solution
Answer: A: 20.0 mm
For a circle, I = πd⁴/64 and A = πd²/4, so k = √(I/A) = √(d²/16) = d/4 = 80/4 = 20.0 mm.
Area properties · Reference Handbook: Statics
