Problem 1 · Laminar and turbulent flow
Oil with a kinematic viscosity of 1.2 × 10⁻⁴ m²/s flows at 3.0 m/s in a 50 mm diameter pipe. The Reynolds number and the flow regime are:
- A.Re ≈ 125,000; turbulent
- B.Re ≈ 625; laminar
- C.Re ≈ 1,250; laminar
- D.Re ≈ 1,250; turbulent
Show the answer and solution
Answer: C: Re ≈ 1,250; laminar
Re = VD/ν = 3.0(0.050)/(1.2 × 10⁻⁴) = 1,250. That is below the transition range of about 2,000 to 2,300, so the flow is laminar. The pipe diameter, not the radius, is the length scale for pipe Reynolds numbers.
Laminar and turbulent flow · Reference Handbook: Fluid Mechanics
